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mishka123456789
@mishka123456789
July 2022
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а)Tga*ctga-(sin^2a-1)/(1-cos^2a)
б)(1-cos^2a)/(1-sin^2a)+ctga*tga
в)(2sin(a-B)+sin(B-a))/(2cos(a-B)-co
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shakuova
А) =1-(-cos^2a)/sin^2a= 1-(-ctg^2a)=1+ctg^2a
б) = sin^2a/cos^2a+1=tg^2a+1
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Answers & Comments
б) = sin^2a/cos^2a+1=tg^2a+1