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wolfstarrkk
@wolfstarrkk
July 2022
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2Cos²(x-π) + 3Sin*(π+x)=0
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nKrynka
2COS^2X - 3SINX = 0
2*(1 - sin^2x) - 3sinx = 0
2sin^2x + 3sinx - 2 = 0
D = 9 + 4*2*2 = 25
x1 = (-3 - 5)/4
x1 = -2
x2 = (-3 + 5)/4
x2 = 1/2
1 votes
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Answers & Comments
2*(1 - sin^2x) - 3sinx = 0
2sin^2x + 3sinx - 2 = 0
D = 9 + 4*2*2 = 25
x1 = (-3 - 5)/4
x1 = -2
x2 = (-3 + 5)/4
x2 = 1/2