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2(1-sin^2x)+2√2sinx-3=0
2-2sin^2x+2√2sinx-3=0
2sin^2x-√8sinx+1=0
D=8-4*2=0
x= -b/2a = √2/2
sinx= √2/2
2(1-sin^2x)+2√2sinx-3=0
2-2sin^2x+2√2sinx-3=0
2sin^2x-√8sinx+1=0
D=8-4*2=0
x= -b/2a = √2/2
sinx= √2/2
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Answers & Comments
x=(-1)^k×arcsin(√2/2)+πk k∈Z
arcsin(√2/2)=π/4
x=(-1)^k×π/4+πk k∈Z