1) M(C3H8) = 12*3 + 1*8 = 44 г/моль
ω = (Ar*n)/M * 100%
ω(С) = 12*3/44 * 100% = 81,8%
ω(H) = 1*8/44 * 100% = 18,2%
Ответ: 81,8% и 18,2%
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
1) M(C3H8) = 12*3 + 1*8 = 44 г/моль
ω = (Ar*n)/M * 100%
ω(С) = 12*3/44 * 100% = 81,8%
ω(H) = 1*8/44 * 100% = 18,2%
Ответ: 81,8% и 18,2%