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юлёкмакарёк
@юлёкмакарёк
July 2022
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Решите пожалуйста Cos1/2x>-√2/2
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nKrynka
Cos(1/2x) > - √2/2
- arccos(-√2/2) + 2πn < (1/2x) < arccos(-√2/2) + 2πn, n∈Z
- 3π/4 + 2πn < 1/2x < 3π/4 + 2πn, n∈Z
- 3π/2 + 4πn < x < 3π/2 + 4πn, n ∈Z
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Answers & Comments
- arccos(-√2/2) + 2πn < (1/2x) < arccos(-√2/2) + 2πn, n∈Z
- 3π/4 + 2πn < 1/2x < 3π/4 + 2πn, n∈Z
- 3π/2 + 4πn < x < 3π/2 + 4πn, n ∈Z