Найти tg a, если cos a=2/ корень из 5 0< a < П/2. Created by nastya51206927. matematika-ru

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Найти tg a, если cos a=2/ корень из 5

0< a < П/2

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mailforazi $cosa= \frac{2}{ \sqrt{5} } \\ \\ sin^2a+cos^2a=1 => sina= \sqrt{1-cos^2a}= \sqrt{1- \frac{4}{5} }= \frac{1}{ \sqrt{5} } \\ \\ tga= \frac{sina}{cosa}= \frac{ \frac{1}{ \sqrt{5} } }{ \frac{2}{ \sqrt{5} } } = \frac{1}{2}$

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