[tex]\displaystyle\bf\\\left \{ {{\dfrac{x+3}{2} -\dfrac{y-2}{3}=2 } \atop {\dfrac{x-1}{4} +\dfrac{y+1}{3} =4}} \right. \\\\\\\left \{ {{\dfrac{x+3}{2} \cdot 6-\dfrac{y-2}{3}\cdot 6=2\cdot 6 } \atop {\dfrac{x-1}{4} \cdot 12+\dfrac{y+1}{3} \cdot 12=4\cdot 12}} \right.\\\\\\\left \{ {{(x+3)\cdot 3-(y-2)\cdot 2=12} \atop {(x-1)\cdot 3+(y+1)\cdot 4=48}} \right. \\\\\\\left \{ {{3x+9-2y+4=12} \atop {3x-3+4y+4=48}} \right.\\\\\\\left \{ {{3x-2y=12-9-4} \atop {3x+4y=48+3-4}} \right.[/tex]

[tex]\displaystyle\bf\\\left \{ {{3x-2y=-1} \ |\cdot 2\atop {3x+4y=47}} \right.\\\\\\+\left \{ {{6x-4y=-2} \atop {3x+4y=47}} \right. \\----------\\9x=45\\\\x=45:9=5\\\\2y=3x+1=3\cdot 5+1=15+1=16\\\\y=16:2=8\\\\Otvet \ : \ \Big(5 \ : \ 8\Big)[/tex]