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August 2022
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Найти наибольшее значения у:
у=6cosx+3√3x+5
на отрезке [0;P/2]
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Dassveta
Возьмем производную.
-6sinx+3√3=0
sinx=0,5√3
x=π/3
y=3+3π/3√3+5=8+π√3
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Answers & Comments
-6sinx+3√3=0
sinx=0,5√3
x=π/3
y=3+3π/3√3+5=8+π√3