сравните arcsin (-√2/2) и arccos (-√2/2). Created by gere76. matematika-ru

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July 2022 1 7 Report

сравните arcsin (-√2/2) и arccos (-√2/2)

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NNNLLL54

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$- \frac{\pi }{2}\ \textless \ arcsinx\ \textless \ \frac{\pi }{2}\; \; \; \Rightarrow \; \; \; arcsin(-\frac{\sqrt2}{2})=-\frac{\pi}{4} \\\\0\ \textless \ arccosx\ \textless \ \pi \; \; \; \Rightarrow \; \; \; arccos(-\frac{\sqrt2}{2})=\frac{3\pi}{4}$

$\frac{3\pi}{4}>-\frac{\pi}{4}$

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