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FreizeDik
@FreizeDik
July 2022
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докажите, что: 2/(√3+1)+1/(√3+2)+1/√2=1+√2/2.
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rossa1783
[2(V3+2)+(V3+1)]/[(V3+1)(V3+2)]+V2/2=
[2V3+4+V3+1]/[(V3+1)(V3+2)]+V2/2=
[3V3+5]/[(3+V3+2V3+2)]+V2/2=
[3V3+5]/[3V3+5]+V2/2=
1+V2/2
1 votes
Thanks 1
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Answers & Comments
[2V3+4+V3+1]/[(V3+1)(V3+2)]+V2/2=
[3V3+5]/[(3+V3+2V3+2)]+V2/2=
[3V3+5]/[3V3+5]+V2/2=
1+V2/2