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temirlanshayhi
@temirlanshayhi
July 2022
1
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t^4-t+1/2>0.
докажите неравенство для t!!!
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СтрельцоваНаташа
Т^4-т+1/2
т^2=2
т^2-т+1/2=0
а= 1 в=-1 с =1/2
-б=1 а*с=-1/2
Д=1-4*-1/2=1-4/1*-1/2=1*2=2
х1= -в±√Д/а*2=1+2/2*1=1
х2=-в±√Д/а*2=1-2/2*1=-1
а дальше как делать я не помню.
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Answers & Comments
т^2=2
т^2-т+1/2=0
а= 1 в=-1 с =1/2
-б=1 а*с=-1/2
Д=1-4*-1/2=1-4/1*-1/2=1*2=2
х1= -в±√Д/а*2=1+2/2*1=1
х2=-в±√Д/а*2=1-2/2*1=-1
а дальше как делать я не помню.