Home
О нас
Products
Services
Регистрация
Войти
Поиск
ChikaTheBest
@ChikaTheBest
July 2022
1
4
Report
найти sin2a cos2a tg2a
если COSA=-12/13
5п/2>а>3п
решите пожалуйста.
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
natalield
Α - угол II четверти
sin2α=2cosα*sinα
найдём sin²α= 1 -cos²α=1-144/169=25/169 ⇒sinα=5/13
sin2α=2*
(-12/13)
*5/13= -120/169
cos2α= cos²α-sin²α=144/169-25/169=119/169
tg2α= sin2α/cos2α =-120/169 : 144/169= -120/144 =-5/6
1 votes
Thanks 8
More Questions From This User
See All
ChikaTheBest
July 2022 | 0 Ответы
uprostite eto vyrazhenie pozhalujsta349d02b254b039d3246a724741ce5c34 55222
Answer
ChikaTheBest
July 2022 | 0 Ответы
poiogite s testom pozhalujsta
Answer
ChikaTheBest
November 2021 | 0 Ответы
371 tretie i chetvyortoe zaranie spasibo
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "2>а>3п решите пожалуйста..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
sin2α=2cosα*sinα
найдём sin²α= 1 -cos²α=1-144/169=25/169 ⇒sinα=5/13
sin2α=2*(-12/13)*5/13= -120/169
cos2α= cos²α-sin²α=144/169-25/169=119/169
tg2α= sin2α/cos2α =-120/169 : 144/169= -120/144 =-5/6