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rieghina
@rieghina
October 2021
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2(х-1)-3(х+2)<6(1+х)
7(у+3)-2(у+2)>2(5у+1)
6(3+5у)-(2+7у)<5(4+3у)
4(3у-1)-3(у-1)>2(3+у)
сделаю лучшим решите
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lekseevaolg
1) 2х-2-3х-6<6+х
-х-8 =0 6+х=0
-х=8 х=-6
х=-8 -8 < -6 верно
2)7у+21-2у-4>10у+2
7у+21-2у-4=0 10у+2=0
5у+17=0 10у=-2
5у=-17 у=-0,2
у=-3.4 -3.4>-0.2 неверно
3) 18+30у-2-2у<20+15у
16+28у <15у-20
16+28у=0 15у-20=0
28у=-16 15у=20
у=-0,57 у=1,3 -0,57<1.3 верно
4)12у-4-3у+3 > 6+2у
9у-1=0 6+2у=0
9у=1 2у=-6
у=0,1 у=-3 0,1>-3 верно
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Answers & Comments
-х-8 =0 6+х=0
-х=8 х=-6
х=-8 -8 < -6 верно
2)7у+21-2у-4>10у+2
7у+21-2у-4=0 10у+2=0
5у+17=0 10у=-2
5у=-17 у=-0,2
у=-3.4 -3.4>-0.2 неверно
3) 18+30у-2-2у<20+15у
16+28у <15у-20
16+28у=0 15у-20=0
28у=-16 15у=20
у=-0,57 у=1,3 -0,57<1.3 верно
4)12у-4-3у+3 > 6+2у
9у-1=0 6+2у=0
9у=1 2у=-6
у=0,1 у=-3 0,1>-3 верно