(2х-3)(2х+3)-1=5х+(х-2)квадр
очень надо,решите плиз..
(2x-3)(2x+3) - 1 = 5x + (x-2)^2
4x^2 - 9 - 1= 5x + x^2-4x + 4
4x^2 - x^2 - 5x + 4x - 9 - 1 - 4= 0
3x^2 - x - 14 = 0
D=169
x1=-2
x2=14/6=7/3
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
(2x-3)(2x+3) - 1 = 5x + (x-2)^2
4x^2 - 9 - 1= 5x + x^2-4x + 4
4x^2 - x^2 - 5x + 4x - 9 - 1 - 4= 0
3x^2 - x - 14 = 0
D=169
x1=-2
x2=14/6=7/3