Сложите алгебраические дроби: (х-1) /(3х-12) -(х-3) /(2х-8)
(x-1)/3x - 12 - x-3/2x-8 =0(x-1) домножаем на (2x - 8 /3x-12 - x-3 домножаем на (3x-12 /2x-8 =0x-1(2x-8) - x - 3(3x-12)/ (3x - 12) - (2x-8) = 0x-2x+8-x-9x+36 / 3x-12-2x-8 = 0-2x+8-9x+36 и 3x-12-2x-8
-9x-2x=-8-36 3x-2x=12+8
-11x=-44 |: (-11) x=20x= 4
(x-1)/(3x-12)-(x-3)/(2x-8)=(x-1)/(3(x-4))-(x-3)/(2(x-4))==(2x-2-3x+9)/(6(x-4))=(7-x)/(6(x-4))
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Answers & Comments
(x-1)/3x - 12 - x-3/2x-8 =0
(x-1) домножаем на (2x - 8 /3x-12 - x-3 домножаем на (3x-12 /2x-8 =0
x-1(2x-8) - x - 3(3x-12)/ (3x - 12) - (2x-8) = 0
x-2x+8-x-9x+36 / 3x-12-2x-8 = 0
-2x+8-9x+36 и 3x-12-2x-8
-9x-2x=-8-36 3x-2x=12+8
-11x=-44 |: (-11) x=20
x= 4
(x-1)/(3x-12)-(x-3)/(2x-8)=(x-1)/(3(x-4))-(x-3)/(2(x-4))=
=(2x-2-3x+9)/(6(x-4))=(7-x)/(6(x-4))