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pollyver
@pollyver
August 2022
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20 БАЛЛОВ!!!
2sinnx(7п/2+х) sinx=√3cosx
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Per4ikPervoiStepeni
2sin(7π/2 + x)*sinx = √3*cosx
2sin(π/2 + x)sinx = √3cosx
2cosxsinx - √3cosx = 0
cosx(2sinx - √3) = 0
1) cosx = 0
x₁ = π/2 + πk, k∈Z
2) 2sinx - √3 = 0
sinx = √3/2
x = (-1)^(n)*arcsin(√3/2) + 2πn, n∈Z
x₂ = (-1)^(n)*(π/3) + 2πn, n∈Z
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Answers & Comments
2sin(π/2 + x)sinx = √3cosx
2cosxsinx - √3cosx = 0
cosx(2sinx - √3) = 0
1) cosx = 0
x₁ = π/2 + πk, k∈Z
2) 2sinx - √3 = 0
sinx = √3/2
x = (-1)^(n)*arcsin(√3/2) + 2πn, n∈Z
x₂ = (-1)^(n)*(π/3) + 2πn, n∈Z