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marina20bella
@marina20bella
July 2022
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Дано натуральное N. Найдите сумму чисел 1/3+1/5+1/7+...+1/(2х+1)
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ShirokovP
Verified answer
Var n, i: word;
sum: real;
begin
write ('n = ');
readln (n);
sum := 0;
for i := 1 to n do
sum := sum + 1/(2*i+1);
writeln (sum:6:5);
end.
2 votes
Thanks 1
ShirokovP
for i := n downto 1 do ?
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Answers & Comments
Verified answer
Var n, i: word;sum: real;
begin
write ('n = ');
readln (n);
sum := 0;
for i := 1 to n do
sum := sum + 1/(2*i+1);
writeln (sum:6:5);
end.