2x³ - x² - 2x + 1 = 0
(2x³ - x²) - (2x - 1) = 0
x²(2x - 1) - (2x - 1) = 0
(x² - 1)(2x - 1) = 0
(x - 1)(x + 1)(2x - 1) = 0
x - 1 = 0 => x = 1
x + 1 = 0 => x = -1
2x - 1 = 0 => x = 1/2
Ответ: x = 1, x = 1/2, x = -1.
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2x³ - x² - 2x + 1 = 0
(2x³ - x²) - (2x - 1) = 0
x²(2x - 1) - (2x - 1) = 0
(x² - 1)(2x - 1) = 0
(x - 1)(x + 1)(2x - 1) = 0
x - 1 = 0 => x = 1
x + 1 = 0 => x = -1
2x - 1 = 0 => x = 1/2
Ответ: x = 1, x = 1/2, x = -1.