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Timurbikk
@Timurbikk
July 2022
2
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Найдите сумму и произведение комплексных чисел z1=7/8(-1/2)i
z2=1-1/2i
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massg
1) сумма (7/8 +1) +( - 1/2 - 1/2)*i = 15/8 - i = 1 7/8 - i
2) произведение 7/8 *1 - 7/8 * 1/2 * i - 1/2 *1*i + 1/2 * 1/2 *i*i = 5/8 - 15/16 i
1 votes
Thanks 1
ahta
7/8=0,875
1/2=0,5
i²=-1
1) z1+z2=(0,875+1)+(-1/2-1/2)i=1,875-i
2) (0.875-0.5i)(1-0.5i)=0.875-0.5i-0.4375i+0.25i²=
(0.875-0.25)+(-0.4375-0.5)i=0.625-0.9375i
0 votes
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Answers & Comments
2) произведение 7/8 *1 - 7/8 * 1/2 * i - 1/2 *1*i + 1/2 * 1/2 *i*i = 5/8 - 15/16 i
1/2=0,5
i²=-1
1) z1+z2=(0,875+1)+(-1/2-1/2)i=1,875-i
2) (0.875-0.5i)(1-0.5i)=0.875-0.5i-0.4375i+0.25i²=
(0.875-0.25)+(-0.4375-0.5)i=0.625-0.9375i