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yuliya3333
@yuliya3333
July 2022
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Для функции f(x)=1/2корень x . Найдите первоначальную, график который проходит через точку А(1;0).
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natali15medved
Verified answer
F(x)=(1/2x^(3/2))/3/2=1/3x√x+C
1/3*1*√1+C=0
C=-1/3
F(x)=1/3x√x-1/3=1/3(x√x-1)
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Answers & Comments
Verified answer
F(x)=(1/2x^(3/2))/3/2=1/3x√x+C1/3*1*√1+C=0
C=-1/3
F(x)=1/3x√x-1/3=1/3(x√x-1)