12-25 cos^2(п-a)tg^2(2п-a) если sina=1/2корня из5. Created by JuliaIvanovaV. algebra-ru

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12-25 cos^2(п-a)tg^2(2п-a) если sina=1/2корня из5

serebrakov2016 12 - 25Сos²(П - a)tg²( 2П - a) = 12 - 25Cos²atg²a = 12-25Cos²a * Sin²a/Cos²a =
= 12 - 25Sin²a если Sina = 1/ 2√5, то
12 - 25 * (1/ 2√5)² = 12 - 25 * 1/20 = 12 - 5/4 = 12 - 1,25 = 10,75

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Universalka Sina = 1/2√5, а не 1/2

Universalka

Verified answer

12+25cos^2 a(формула приведения) * (-tg^2 a)(формула пивед.) =
12+25cos^2a*(-sin^2a/cos^2a)=12-25sin^2a=12-25*(1/2*)^2=
12-25*1/4*5=12-31,25=-19,25

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