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SVETKAKONVETKA
@SVETKAKONVETKA
March 2022
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2lg(-x)>lg(x+6) одз: х+6>0, х>-6
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Хуqожнuк
Одз:
x+6 > 0
-x > 0
x > -6
x < 0
2lg(-x) > lg(x+6)
lg(-x)^2 > lg(x+6)
x^2 > x + 6
x^2 - x - 6 > 0
x < -2
x > 3 (не принадлежит одз)
x < -2,
x > -6,
x < 0, откуда -6 < x < -2
Ответ: (-6; -2)
2 votes
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Answers & Comments
x+6 > 0
-x > 0
x > -6
x < 0
2lg(-x) > lg(x+6)
lg(-x)^2 > lg(x+6)
x^2 > x + 6
x^2 - x - 6 > 0
x < -2
x > 3 (не принадлежит одз)
x < -2,
x > -6,
x < 0, откуда -6 < x < -2
Ответ: (-6; -2)