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horoshayaya
@horoshayaya
December 2021
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log(1/2)*log(2)*log(x-1) 9 >0
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jama9508
log(1/2)log(2)log(x-1)9 >0 ОДЗ: x-1>0
log(1/2)log(2)log(x-1)9 >log(1/2)1 x>1
log(2)log(x-1)9 <1
log(2)log(x-1)9 <log(2)2
log(x-1)9 <2
(x-1)²>9
x²-2x+1-9>0
x²-2x-8>0
x ∈ (-∞;-2)U(4;∞)
После пересечения с ОДЗ получаем:
x ∈ (4;∞)
5 votes
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Answers & Comments
log(1/2)log(2)log(x-1)9 >log(1/2)1 x>1
log(2)log(x-1)9 <1
log(2)log(x-1)9 <log(2)2
log(x-1)9 <2
(x-1)²>9
x²-2x+1-9>0
x²-2x-8>0
x ∈ (-∞;-2)U(4;∞)
После пересечения с ОДЗ получаем:
x ∈ (4;∞)