2log4log16 256+ log√2. 8=. Created by 774848fjbdbdbd. algebra-ru

2log4log16 256+ log√2. 8=...

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$2 log_{ {2}^{2} }( log_{4^{2} }(4^{4} ) ) + log_{ \sqrt{2} }( {2}^{3} ) = \\ = 2 log_{ {2}^{2} }(2) + log_{ 2^{ \frac{1}{2}} }(8) = \\ = 2 log_{ {2}^{2} }(2) + 6 = 2 \times \frac{1}{2} + 6 = \\ = 1 + 6 = 7$
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