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July 2022 2 5 Report

Вычислите значение tgæ, если sinæ=3/5 и п/2<æ<п .

MillyMoon $sin^2 \alpha+cos^2 \alpha=1$
$\frac{\pi}{2} < \alpha < \pi; cos \alpha$
$cos \alpha=-\sqrt{1-sin^2 \alpha}=-\sqrt{1-(\frac{3}{5})^2}=-\frac{4}{5}$
$tg \alpha=\frac{sin \alpha}{cos \alpha}=\frac{\frac{3}{5}}{-\frac{4}{5}}=-\frac{3}{4}$

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dtnth

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Cos ae В КВАДРАТЕ =1-sin В КВАДРАТЕ=1-9/25=16/25
n/2<ae<n значит ae -2 четверть, тогда cos =4/5
tgae=sinae/cosae=3/5 : 4/5 = 3/4

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