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GoldGriffon
@GoldGriffon
July 2022
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найти cosα, tgα, ctgα если sinα=5/13 и π/2<α<π
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Lesben
Verified answer
Sinα=5/13, α∈(π/2, π)
cosα=-√(1-sin²α)=-√(1-25/169)=-√(144/169)=-12/13
tgα=sinα/cosα=(5/13)/(-12/13)=-5/12
ctgα=1/tgα=1/(-5/12)=-12/5
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Answers & Comments
Verified answer
Sinα=5/13, α∈(π/2, π)cosα=-√(1-sin²α)=-√(1-25/169)=-√(144/169)=-12/13
tgα=sinα/cosα=(5/13)/(-12/13)=-5/12
ctgα=1/tgα=1/(-5/12)=-12/5