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Астя07
@Астя07
August 2022
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Срочно!
Найти sin 2a,cos 2a,tg 2a, если sin a=1/3 П/2<а<П
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Answers & Comments
aniutapavlova
Cos a =
= 2
/3
sin 2a = 2sin a cos a = 2*1/3*2
/3 = 2
/3
tg a = sina/cos a = 1/
tg 2a = 2tga/1-tg^2a = (1/
) / 1 - 1/8 = 8/7
6 votes
Thanks 5
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Answers & Comments
sin 2a = 2sin a cos a = 2*1/3*2/3 = 2/3
tg a = sina/cos a = 1/
tg 2a = 2tga/1-tg^2a = (1/) / 1 - 1/8 = 8/7