6a-20b при а=1/2(m-n),b=0,5(m+n) помогите пж. Created by serikalina05. matematika-ru

2(m-n),b=0,5(m+n) помогите пж...

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6a-20b при а=1/2(m-n),b=0,5(m+n)
помогите пж

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kolobok1431 6a-20b
при а=1/2(m-n); b=0,5(m+n)
6 · 1/2(m-n) - 20 · 0,5(m+n) = 3(m-n) - 10(m+n) = 3m-3n - 10m-10n=
= - 7m - 13n = - (7m + 13n)
Ответ: - (7m+13n)

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9z 73 8z375238 11z 7 z stolko vidov rastenij v zapovednikea546725d5ef2105664cb5198885c17e1 15952

9z 73 8z375238 11z 7 z stolko vidov rastenij v zapovednike

najdite koren uravneniya i vy uznaete o korgalzhynskom zapovednike kotoryj nahod

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