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joker1995i
@joker1995i
August 2022
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Найти первообразную F(x) функции f(x) , график которой проходит через точку М(х,у) : f(x)=1+x/2;M(1;3) и f(x)=2+4x; M(-1;1)
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mikael2
Verified answer
∫(1+x/2)dx=x+x²/4+c M(1;3)
1+1/4+c=3 ⇒c=3-5/4=7/4
x+x²/4+7/4
∫(2+4x)dx=2x+2x²+c
M(-1;1) ⇒ -2+2+c=1 c=1
2x+2x²+1
1 votes
Thanks 2
joker1995i
а можно график сам
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Answers & Comments
Verified answer
∫(1+x/2)dx=x+x²/4+c M(1;3)1+1/4+c=3 ⇒c=3-5/4=7/4
x+x²/4+7/4
∫(2+4x)dx=2x+2x²+c
M(-1;1) ⇒ -2+2+c=1 c=1
2x+2x²+1