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84776v
@84776v
July 2022
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Помогите сократить дробь
Помогите сократить дробь :10^(n+5)/(2^(n+3)*5^(n+2))
по подробней если можно)
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mmb1
Verified answer
10^(n+5)/(2^(n+3)*5^(n+2))=10^n10^5/(2^3*2^n*5^2*5^n)=10^5/2^3*5^2=10^3/2=1000/2=500
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Midhat1997
10^n*10^5 -поправка
Midhat1997
10^(n+5)/(2^(n+3)*5^(n+2))=10^(n+5)/(2^(n+2)*5^(n+2)*2)=10^(n+5)/((2*5)^(n+2)*2)=10^(n+5)/(10^(n+2)*2)=10^3/(1*2)=1000/2=500.
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Verified answer
10^(n+5)/(2^(n+3)*5^(n+2))=10^n10^5/(2^3*2^n*5^2*5^n)=10^5/2^3*5^2=10^3/2=1000/2=500