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ttm1
@ttm1
August 2022
1
4
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найти предел при n стремящейся к бесконечности от
(2^(n+1)+3^(n+1))/(2^n+3^n)
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армения20171
Lim(2^(n+1)+3^(n+1))/(2^n+3^n)=
n=>oo
lim(2*2^n+2*3^n+3^n)/(2^n+3^n)=
lim(2+3^n/(2^n+3^n)=
lim(2+1-2^n/(2^n+3^n)=
3
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Answers & Comments
n=>oo
lim(2*2^n+2*3^n+3^n)/(2^n+3^n)=
lim(2+3^n/(2^n+3^n)=
lim(2+1-2^n/(2^n+3^n)=
3