Home
О нас
Products
Services
Регистрация
Войти
Поиск
Nataliavikman
@Nataliavikman
July 2022
1
1
Report
решение уравнений в) 1/2(4-3 целых 1/2х)=1 целая 1/4х-1/2.очень срочно, помогите пожалуйста
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
TigerYa
Verified answer
В) 1/2(4-3 целых 1/2х)=1 целая 1/4х-1/2
1/2•4 - 1/2• 3 1/2х= 1 1/4х -1/2
2- 1/2• (2•3+1)/2Х= (4•1+1)/4Х- 1/2
2- 1/2• 7/2Х=5/4Х -1/2
2- 7/4Х = 5/4Х -1/2
2+ 1/2= 5/4Х+ 7/4Х
2 1/2= 12/4Х
2 1/2= 3Х
Х= 2 1/2 : 3
Х= (2•2+1)/2 • 1/3
Х= 5/2• 1/3
Х= 5/6
Проверка
в) 1/2(4-3 целых 1/2х)=1 целая 1/4х-1/2
1/2•(4- 3 1/2• 5/6) =1 1/4• 5/6 -1/2
1/2•(4 -(3•2+1)/2• 5/6)= (4•1+1)/4• 5/6-1/2
1/2• (4- 7/2• 5/6)= 5/4• 5/6 -1/2
1/2• (4- 35/12)= 25/24- 1/2
1/2• (4- 2 11/12)= 25/24- (1•12)/(2•12)
1/2• (3 12/12- 2 11/12)= 25/24- 12/24
1/2• (1 1/12)= 13/24
1/2• (12•1+1)/12= 13/24
1/2• 13/12= 13/24
13/24= 13/24.
В десятичных.
в) 1/2(4-3 целых 1/2х)=1 целая 1/4х-1/2
0,5• (4- 3,5х)= 1,25х- 0,5
0,5•4- 0,5• 3,5х= 1,25х-0,5
2- 1,75х= 1,25х-0,5
2+0,5= 1,25х+ 1,75х
2,5= 3х
Х= 2,5:3
Х=25/10•1/3
Х= 5/2• 1/3
Х= 5/6.
13 votes
Thanks 17
More Questions From This User
See All
Nataliavikman
July 2022 | 0 Ответы
2 3u ochen srochno pozhalujsta pomogite
Answer
Nataliavikman
July 2022 | 0 Ответы
pomogite pozhalujsta nomera 31 i 32
Answer
Nataliavikman
July 2022 | 0 Ответы
5pomogite pozhalujsta srochno nuzhno
Answer
Nataliavikman
July 2022 | 0 Ответы
2 3u ochen srochno pozhalujsta pomogite i napishite resheniepliz
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "2.очень срочно, помогите пожалуйста..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
В) 1/2(4-3 целых 1/2х)=1 целая 1/4х-1/21/2•4 - 1/2• 3 1/2х= 1 1/4х -1/2
2- 1/2• (2•3+1)/2Х= (4•1+1)/4Х- 1/2
2- 1/2• 7/2Х=5/4Х -1/2
2- 7/4Х = 5/4Х -1/2
2+ 1/2= 5/4Х+ 7/4Х
2 1/2= 12/4Х
2 1/2= 3Х
Х= 2 1/2 : 3
Х= (2•2+1)/2 • 1/3
Х= 5/2• 1/3
Х= 5/6
Проверка
в) 1/2(4-3 целых 1/2х)=1 целая 1/4х-1/2
1/2•(4- 3 1/2• 5/6) =1 1/4• 5/6 -1/2
1/2•(4 -(3•2+1)/2• 5/6)= (4•1+1)/4• 5/6-1/2
1/2• (4- 7/2• 5/6)= 5/4• 5/6 -1/2
1/2• (4- 35/12)= 25/24- 1/2
1/2• (4- 2 11/12)= 25/24- (1•12)/(2•12)
1/2• (3 12/12- 2 11/12)= 25/24- 12/24
1/2• (1 1/12)= 13/24
1/2• (12•1+1)/12= 13/24
1/2• 13/12= 13/24
13/24= 13/24.
В десятичных.
в) 1/2(4-3 целых 1/2х)=1 целая 1/4х-1/2
0,5• (4- 3,5х)= 1,25х- 0,5
0,5•4- 0,5• 3,5х= 1,25х-0,5
2- 1,75х= 1,25х-0,5
2+0,5= 1,25х+ 1,75х
2,5= 3х
Х= 2,5:3
Х=25/10•1/3
Х= 5/2• 1/3
Х= 5/6.