Ответ: 41π/32 13π/16
Пошаговое объяснение: 10π - 8х =+- arccos √2/2 10π - 8х =+-π/4+2nπ, n∈Z 8x=10π+-π/4 -2nπ, n∈Z 1) 8x=41π/4-2nπ, n∈Z , х₁=41π/32-2nπ, n∈Z
2) 8x=39π/4-2nπ, n∈Z , х₂=39π/32-2nπ, n∈Z х₂=13π/16-2nπ, n∈Z
Выберем корни на [π/2;π] при n=0 х₁=41π/32 x₂=13π/16
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Ответ: 41π/32 13π/16
Пошаговое объяснение: 10π - 8х =+- arccos √2/2 10π - 8х =+-π/4+2nπ, n∈Z 8x=10π+-π/4 -2nπ, n∈Z 1) 8x=41π/4-2nπ, n∈Z , х₁=41π/32-2nπ, n∈Z
2) 8x=39π/4-2nπ, n∈Z , х₂=39π/32-2nπ, n∈Z х₂=13π/16-2nπ, n∈Z
Выберем корни на [π/2;π] при n=0 х₁=41π/32 x₂=13π/16