Home
О нас
Products
Services
Регистрация
Войти
Поиск
deanonm
@deanonm
June 2022
1
12
Report
16^cos^2x+16^sin^2x=10 на [-pi/2;pi]
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
LyubaAlexandorovna
16^(cos^2x)+16^(1-cos^2x)=10
16^(cos^2x)+16/16^(cos^2x)-10=0
Заменим 16^(cos^2x)=t
t+16/t-10=0 (*t)
t^2-10*t+16=0
t1,2=(10±√(100-64))/2=(10±6)/2
t1=2 16^(cos^2x)=2 2^(4*cos^2x)=2^1 4*cos^2x=1 cos^2x=1/4 cosx=±1/2 x=±П/3+Пn, nЄZ
t2=8 16^(cos^2x)=8 2^(4*cos^2x)=2^3 4*cos^2x=3 cos^2x=3/4
cosx=±√3/2 x=±П/6+Пm, mЄZ
[-П/2; П] х=-П/3; -П/6; П/6; П/3; 2*П/3; 5*П/6
2 votes
Thanks 1
deanonm
Спасибо
More Questions From This User
See All
deanonm
August 2022 | 0 Ответы
kak 2x23x2 zapisat v vide ab2
Answer
deanonm
August 2022 | 0 Ответы
4 x2 najti integral
Answer
deanonm
August 2022 | 0 Ответы
pensionnyj fond vladeet cennymi bumagami kotorye stoyat t tys rublej v konce g08307bd160bfc100a391dabcca782582 60810
Answer
deanonm
August 2022 | 0 Ответы
obem piramidy sabc raven 54 na rebrah sa av i as vzyaty tochki m n i r sootvet2999df4a07170c7cf671530bd775f4f9 96123
Answer
deanonm
August 2022 | 0 Ответы
tex]...
Answer
deanonm
August 2022 | 0 Ответы
verno legkoe uravnenie
Answer
deanonm
August 2022 | 0 Ответы
31 dekabrya 2013 goda sergej vzyal v banke 9 930 000 rublej v kredit pod 10 godov44bcf8d80c6c43bed532ddb93264fd06 30255
Answer
deanonm
August 2022 | 0 Ответы
2]...
Answer
deanonm
August 2022 | 0 Ответы
3 const287500 pa gaz nachinaet szhimat kakoj naibolshij obem mozhet zanimat
Answer
deanonm
August 2022 | 0 Ответы
napisat obshij vyvod cel rabotynauchitsya opytnym putem poluchat sobirat i ra
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "2;pi]..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
16^(cos^2x)+16/16^(cos^2x)-10=0
Заменим 16^(cos^2x)=t
t+16/t-10=0 (*t)
t^2-10*t+16=0
t1,2=(10±√(100-64))/2=(10±6)/2
t1=2 16^(cos^2x)=2 2^(4*cos^2x)=2^1 4*cos^2x=1 cos^2x=1/4 cosx=±1/2 x=±П/3+Пn, nЄZ
t2=8 16^(cos^2x)=8 2^(4*cos^2x)=2^3 4*cos^2x=3 cos^2x=3/4
cosx=±√3/2 x=±П/6+Пm, mЄZ
[-П/2; П] х=-П/3; -П/6; П/6; П/3; 2*П/3; 5*П/6