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АnyaKilina
@АnyaKilina
August 2022
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sin2a= 2tga/1+tg²a , если а≠π/2+πn,n∈z пожалуйста
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nKrynka
Решение
Применим формулу:
sinα = (2tg(α/2)) / (1 + tg^2(α/2))
sin2α = (2tg(α) / (1 + tg^2(α))
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Answers & Comments
Применим формулу:
sinα = (2tg(α/2)) / (1 + tg^2(α/2))
sin2α = (2tg(α) / (1 + tg^2(α))