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cricker
@cricker
July 2022
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Вычисли все корни уравнения 2√3 tgx - 6 = 0 на промежутке ( - 3 Пи/2 ; 3 Пи/2)
ПОЖАЛУЙСТА, ПОМОГИТЕ!
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srzontmp
2√3tgx =6 -> tgx = 6/2√3 = 3/√3 = √3 -> x =Пи/3 + Пи*n , n ∈ Z
n = -1 -> x = -2/3Пи, n =0 -> x = Пи/3, n = 1, -> x = 4/3Пи
На интервале (- 3/2Пи ; 3/2Пи) всего три корня
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Answers & Comments
n = -1 -> x = -2/3Пи, n =0 -> x = Пи/3, n = 1, -> x = 4/3Пи
На интервале (- 3/2Пи ; 3/2Пи) всего три корня