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Sonya18w825
@Sonya18w825
July 2022
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2sin14x×cos7x+sin7x=0
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hlopushinairina
2sin14xcos7x+sin7x=0;
4sin7xcos²7x+sin7x=0;
sin7x(4cos²7x+1)=0;
sin7x=0;⇒7x=nπ;n∈Z;⇒x=nπ/7;n∈Z;
cos²7x=-1/4⇒cos²7x>0⇒нет решения.
1 votes
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hlopushinairina
cos^2 (7x)<0-->нет решения
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Answers & Comments
4sin7xcos²7x+sin7x=0;
sin7x(4cos²7x+1)=0;
sin7x=0;⇒7x=nπ;n∈Z;⇒x=nπ/7;n∈Z;
cos²7x=-1/4⇒cos²7x>0⇒нет решения.