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AikoB
@AikoB
August 2021
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4(cos20-sin20)/ √2sin25
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sedinalana
Verified answer
4(cos20-sin20)/(√2sin25)=4(cos20-cos70)/(√2sin25)
=-8*sin45*sin(-25)/(√2sin25)=4√2sin25/(√2sin25)=4
------------------------------------------------------------------------------
sin20=sin(90-70)=cos70
cosa-cosb=-2sin[(a+b)/2*sin(a-b)/2]
8 votes
Thanks 15
AikoB
спасибо большое
AikoB
эммм Вы можете объяснить откуда Вы взяли (соs70) и sin45*sin (-25 ) и куда дел я cos20 который стоял в начале
AikoB
куда делся
AikoB
извини, ещё -8 откуда?
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Verified answer
4(cos20-sin20)/(√2sin25)=4(cos20-cos70)/(√2sin25)=-8*sin45*sin(-25)/(√2sin25)=4√2sin25/(√2sin25)=4
------------------------------------------------------------------------------
sin20=sin(90-70)=cos70
cosa-cosb=-2sin[(a+b)/2*sin(a-b)/2]