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rytell1
@rytell1
August 2022
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2sin^2x-3sinx*cosx+cos^2x=1
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sedinalana
Verified answer
2sin²x-3sinxcosx+cos²x-sin²x-cos²x=0sin²x-3sinxcosx=0
sinx(sinx-3cosx)=0
sinx=0⇒x=πn,n∈z
sinx-3cosx=0/cosx
tgx-3=0
tgx=3⇒x=arctg3+⇒n,n∈z
2 votes
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Answers & Comments
Verified answer
2sin²x-3sinxcosx+cos²x-sin²x-cos²x=0sin²x-3sinxcosx=0sinx(sinx-3cosx)=0
sinx=0⇒x=πn,n∈z
sinx-3cosx=0/cosx
tgx-3=0
tgx=3⇒x=arctg3+⇒n,n∈z