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H1GH3LL
@H1GH3LL
July 2022
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2sin2x-sin^2x=3cos^2x
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kirichekov
Verified answer
2sin2x-sin²x=3cos²x,
2*(2sinx*cosx)-sin²x-3*cos²x=0 |: cos²x≠0
4tgx-tg²x-3=0 тригонометрическое квадратное уравнение, замена переменной: tgx=y
-y²+4y-3=0. y₁=-3, y₂=1
обратная замена:
∈Z
∈Z
ответ:
n∈Z
18 votes
Thanks 51
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Answers & Comments
Verified answer
2sin2x-sin²x=3cos²x,2*(2sinx*cosx)-sin²x-3*cos²x=0 |: cos²x≠0
4tgx-tg²x-3=0 тригонометрическое квадратное уравнение, замена переменной: tgx=y
-y²+4y-3=0. y₁=-3, y₂=1
обратная замена:
∈Z
∈Z
ответ:
n∈Z