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alfinos1
@alfinos1
July 2022
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3sin^2x+1/2sin2x=2cos^2x
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Удачник66
Verified answer
3sin^2 x + 1/2*2sin x*cos x - 2cos^2 x = 0
Делим все на cos^2 x
3tg^2 x + tg x - 2 = 0
(tg x + 1)(3tg x - 2) = 0
tg x = -1; x1 = pi/4 + pi*k
tg x = 2/3; x2 = arctg(2/3) + pi*n
1 votes
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Luluput
Verified answer
Разделим почленно на sin²x≠0
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2 votes
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Answers & Comments
Verified answer
3sin^2 x + 1/2*2sin x*cos x - 2cos^2 x = 0Делим все на cos^2 x
3tg^2 x + tg x - 2 = 0
(tg x + 1)(3tg x - 2) = 0
tg x = -1; x1 = pi/4 + pi*k
tg x = 2/3; x2 = arctg(2/3) + pi*n
Verified answer
Разделим почленно на sin²x≠0
Замена:
или
∈ или ∈