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dayana51
@dayana51
August 2022
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2sin^2x=под корень3 sin2x
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Akkee
Sin2x=2sinx*cosx
2sin^2x=√3*2*sinx*cosx
sinx=√3cosx
sin(x-П/3)=0
x-П/3=Пn
x=Пn-П/3
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Answers & Comments
2sin^2x=√3*2*sinx*cosx
sinx=√3cosx
sin(x-П/3)=0
x-П/3=Пn
x=Пn-П/3