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Wildsakura
@Wildsakura
April 2021
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2*(sin^4 альфа + sin^2 альфа * cos ^2 альфа + cos^4 альфа)-(sin^8 альфа + cos ^8 альфа) Упростите выражение.
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oganesbagoyan
Verified answer
Task/25768411
--------------------
Упростите выражение 2(sin⁴α+sin²α*cos²α +cos⁴α) -(sin⁸α +cos⁸α)
---------------------------
2(sin⁴α+sin²α*cos²α +cos⁴α) -(sin⁸α +cos⁸
α) =
(sin⁴α+2sin²α*cos²α +cos⁴α)
+ sin⁴α+cos⁴α -(sin⁸α +cos⁸
α) =
(sin²α+cos²α)² + (sin⁴α - sin⁸α) + (cos⁴α -cos⁸
α) =
1 +sin⁴α(1 -sin⁴α) +cos⁴α(1 -cos⁴
α) =
1 +
sin⁴α*
(1 -sin²α)
(1+sin²α) +cos⁴α*
(1 -cos²α)
(1+cos²
α) =
1 +sin⁴α*
cos²α*
(1+sin²α) +cos⁴α*
sin
²α *
(1+cos²
α) =
1 +sin²α*cos²α
*
(
sin²α
+sin⁴α +
cos²α
+cos⁴α) =
1 +sin²α*cos²α
*
(1+sin⁴α +cos⁴α) =
1 +sin²α*cos²α
*(
1+(
sin²
α
+cos²α
)² - 2sin²α *cos²
α
)
=
1 +sin²α*cos²α
*(
2 - 2sin²α *cos²
α
)
=1 +(
sinα*cosα)²
(
2-2(sinα *cosα)²
)
=
1 +(1/4)sin²2α (2 - (1/2)*sin²2α) = 1 +(1/8)sin²2α (4 - sin²2
α)=
1 +(1/32)*( 1-cos4α) (7 +cos4α)
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Verified answer
Task/25768411--------------------
Упростите выражение 2(sin⁴α+sin²α*cos²α +cos⁴α) -(sin⁸α +cos⁸α)
---------------------------
2(sin⁴α+sin²α*cos²α +cos⁴α) -(sin⁸α +cos⁸α) =
(sin⁴α+2sin²α*cos²α +cos⁴α) + sin⁴α+cos⁴α -(sin⁸α +cos⁸α) =
(sin²α+cos²α)² + (sin⁴α - sin⁸α) + (cos⁴α -cos⁸α) =
1 +sin⁴α(1 -sin⁴α) +cos⁴α(1 -cos⁴α) =
1 +sin⁴α*(1 -sin²α)(1+sin²α) +cos⁴α*(1 -cos²α)(1+cos²α) =
1 +sin⁴α*cos²α*(1+sin²α) +cos⁴α*sin²α *(1+cos²α) =
1 +sin²α*cos²α*(sin²α+sin⁴α +cos²α+cos⁴α) =
1 +sin²α*cos²α*(1+sin⁴α +cos⁴α) =
1 +sin²α*cos²α*(1+(sin²α +cos²α)² - 2sin²α *cos²α) =
1 +sin²α*cos²α*(2 - 2sin²α *cos²α) =1 +(sinα*cosα)² (2-2(sinα *cosα)² ) =
1 +(1/4)sin²2α (2 - (1/2)*sin²2α) = 1 +(1/8)sin²2α (4 - sin²2α)=
1 +(1/32)*( 1-cos4α) (7 +cos4α)