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Solnцe22
@Solnцe22
April 2021
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√2×sin(альфа-45градусов)-sin альфа - cos альфа
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manyny06
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Решение смотри на фотограФИИ
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mikael2
Sin(α−β)=sin(α)·cos(β)−cos(α)·sin(β
) используем эту формулу
sin(a-45
°)=sinacos45-cosasin45=√2/2*sina-√2/2cosa
√2*(√2/2*sina-√2/2cosa)=sina-cosa
sina-cosa-sina-cosa=-2cosa
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Verified answer
Решение смотри на фотограФИИsin(a-45°)=sinacos45-cosasin45=√2/2*sina-√2/2cosa
√2*(√2/2*sina-√2/2cosa)=sina-cosa
sina-cosa-sina-cosa=-2cosa