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leshik1112
@leshik1112
August 2022
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2sin²X - 2sinXcosX=1
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JaOw
Task/25148335
--------------------
2sin²x - 2sinxcosx=1 ;
- 2sinxcosx= 1 -2sin²x;
* * * 1 - 2sin²x=cos²x+sin²x -2sin²x =cos²x-sin²x =cos2x * * *
-sin2x =cos2x ;
sin2x = -cos2x || :cos2x≠ 0
tg2x = -1
2x = -π/4 +π*k , k∈
ℤ
x= -
π/8 +(π/2)*k , k∈ℤ .
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oganesbagoyan
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oganesbagoyan
2sin²X - 2sinXcosX=1 ⇔sin²X - 2sinXcosX-cos²X=0⇔ tg²X -2tgX -1 =0
oganesbagoyan
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Answers & Comments
--------------------
2sin²x - 2sinxcosx=1 ;
- 2sinxcosx= 1 -2sin²x;
* * * 1 - 2sin²x=cos²x+sin²x -2sin²x =cos²x-sin²x =cos2x * * *
-sin2x =cos2x ;
sin2x = -cos2x || :cos2x≠ 0
tg2x = -1
2x = -π/4 +π*k , k∈ℤ
x= -π/8 +(π/2)*k , k∈ℤ .
Verified answer
Ответ & & & & & & & & & & & & & & &