cos(t)*ctg(pi/2+t) / cos(pi/2+t). Created by Поляч2000. algebra-ru

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Поляч2000 @Поляч2000

July 2022 1 19 Report

cos(t)*ctg(pi/2+t) / cos(pi/2+t)

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$\frac{Cost * ctg( \frac{ \pi }{2}+t) }{Cos( \frac{ \pi }{2} + t)} = \frac{Cost * (-tgt)}{- Sint} = \frac{Cost * \frac{Sint}{Cost} }{Sint} = \frac{Sint}{Sint} = 1$

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