2+В):5cos(В-П)...

katenaorlova00 @katenaorlova00

November 2021 1 3 Report

2cos(3П-В)-sin(П/2+В):5cos(В-П)

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zarembo73 2cos(3π-β)-sin(π/2+β):5cos(β-π)=(2cos(2π+(π-β))-cosβ)/5cos(π-β)=
=(2cos(π-β)-cosβ)/-5cosβ=(-2cosβ-cosβ)/-5cosβ=-3cosβ/-5cosβ=3/5=0,6.

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