ОДЗ: x≥1
4(x-1)+4√(x²+2x-3)+x+3=4
4√(x²+2x-3)=5-5x
x≤1
16(x²+2x-3)=25-50x+25x²
16x²+32x-48=25-50x+25x²
-9x²+82x-73=0
9x²-82x+73=0
D=6724-2628=4096
x1=(82+64)/18=73/9 - не корень
x2=(82-64)/18=1
Ответ: x=1
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Verified answer
ОДЗ: x≥1
4(x-1)+4√(x²+2x-3)+x+3=4
4√(x²+2x-3)=5-5x
x≤1
16(x²+2x-3)=25-50x+25x²
16x²+32x-48=25-50x+25x²
-9x²+82x-73=0
9x²-82x+73=0
D=6724-2628=4096
x1=(82+64)/18=73/9 - не корень
x2=(82-64)/18=1
Ответ: x=1