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Saytinybird
@Saytinybird
July 2022
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Решите неравенства (60 б)
a)-x^2-10≤7x
b)-x^2+8x≥16
c)(4x-1)(x^2-4)<0
D)(2x+5)(4x+3)(7-2x)(x-3)<0
e)((x+1)(x+2)(x+3)/(2x-1)(x+4)(x-3))≤0
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NNNLLL54
Verified answer
1) -x²-10≤7x
x²+7x+10≥0 , x=-5 или x=-2
(x+5)(x+2)≥0 +++[-5]---[-2]+++
x∈(-∞,-5]U[-2,+∞)
2) -x²+8x≥16
x²-8x+16≤0
(x-4)²≤0 +++++[4]+++++
x=4
3) (4x-1)(x²-4)<0
(4x-1)(x-2)(x+2)<0 - - - (-2)+++(1/4) - - - (2)+++
x∈(-∞,-2)U(1/4,2)
4) (2x+5)(4x+3)(7-2x)(x-3)<0
(2x+5)(4x+3)(2x-7)(x-3)>0
+++(-2,5) - - - (-0,75)+++(3) - - - (3,5) +++
x∈(-∞; -2,5)U(-0,75 ; 3)U(3,5 ;+∞)
5) (x+1)(x+2)(x+3)(2x-)(x+4)(x-3)≤0
+++(-4) - - - (-3)+++(-2) - - - (-1)+++(1/2) - - - (3)+++
x∈(-4,-3)U(-2,-1)U(1/2,3)
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ВладимирБ
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Решение смотри в приложении
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Answers & Comments
Verified answer
1) -x²-10≤7xx²+7x+10≥0 , x=-5 или x=-2
(x+5)(x+2)≥0 +++[-5]---[-2]+++
x∈(-∞,-5]U[-2,+∞)
2) -x²+8x≥16
x²-8x+16≤0
(x-4)²≤0 +++++[4]+++++
x=4
3) (4x-1)(x²-4)<0
(4x-1)(x-2)(x+2)<0 - - - (-2)+++(1/4) - - - (2)+++
x∈(-∞,-2)U(1/4,2)
4) (2x+5)(4x+3)(7-2x)(x-3)<0
(2x+5)(4x+3)(2x-7)(x-3)>0
+++(-2,5) - - - (-0,75)+++(3) - - - (3,5) +++
x∈(-∞; -2,5)U(-0,75 ; 3)U(3,5 ;+∞)
5) (x+1)(x+2)(x+3)(2x-)(x+4)(x-3)≤0
+++(-4) - - - (-3)+++(-2) - - - (-1)+++(1/2) - - - (3)+++
x∈(-4,-3)U(-2,-1)U(1/2,3)
Verified answer
Решение смотри в приложении