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МякC
@МякC
August 2022
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cos2x+2√2sin(п/2+x)-2=0
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LordByron
Cos^2x-sin^2x+2
cosx-2sin^2x-2cos^2x=0-cos^2x-3sin^2x+2sqrt2cosx=0-cos^2x-3+3cos^2x+2sqrt2cosx=02cos^2x+2sqrt2cosx-3=0cos1,2=sqrt2/2; посторонний корень (не входит в о.о.cos)Cosx=sqrt2/2X=+-П/4+2Пк;к принадлежит z
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